Using the formula given: d = <span>√(3h/2)
We simply substitute the given values of h into the equation and compare the results.
For Wyatt where h = 120:
d = </span>√(3(120)/2)<span>
d = 13.42 miles
</span><span>For Shawn where h = 270:
d = </span>√(3(270)/2)<span>
d = 20.12 miles
</span>
Since the question asks for how much farther can Shawn see, we subtract the results:
20.12 - 13.42 = 6.7
Therefore, Shawn can see 6.7 miles farther.
Answer: 32
Step-by-step explanation:
we have in this case right triangle with a leg equal to 24 and a hypotenuse equal to 40
c^2=a^2+b^2
40^2=24^2+b^2
b^2=1600-576=1024
b=sqrt1024=32
The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j
Hence the answer is:
v*w=(-42i+20j)
C=(-10;5). If you want an explanation I would be happy to explain it
D, because the will not intersect i believe
