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tatyana61 [14]
3 years ago
8

A number greater than 1000 who is prime factorization contains one prime number that does not repeat one prime number that repea

t three times and one prime number that repeats twice
Mathematics
1 answer:
charle [14.2K]3 years ago
5 0
Let the prime number which does not repeat be a, the prime number which repeats twice be b, the prime number which repeats 3 times be c.

Then the prime factorization of this number is a\cdot b^2 \cdot c^3.



Let's find the prime factorization of 1000:

1000=10^3=(2 \cdot5)^3=2^3 \cdot5^3


So let c= 5, b be a number such that b^2>2^3=8, for example let b = 3, and let a be any prime, for example 2


thus the number is a\cdot b^2 \cdot c^3=2\cdot 3^2 \cdot 5^3=2 \cdot 9 \cdot 125=9 \dot 250=2250


Answer: 2250
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