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Rasek [7]
3 years ago
15

Is k=6 a solution to the equation: 1/3k = 3

Mathematics
2 answers:
Step2247 [10]3 years ago
8 0

Answer: No it's not

Step-by-step explanation:

1/3 x 6/1 = 6/3

6/3 = 2

Semenov [28]3 years ago
6 0

Answer:

No

Step-by-step explanation:

1/3 x 6 = 2, not 3

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Cold antoje help me answering this please :).<br>Fake answer will be reported. ​
Harrizon [31]

Answer:

158.1

Step-by-step explanation:

Distance is the square root of (x1-x2)^2+(y1-y2)^2

square root of (-4-146)^2+(2-52)^2

square root of 150^2+50^2

square root of 22500+2500

square root of 25000

50sqrt10

Rounding is 158.1

5 0
3 years ago
Sally gave her brother $3.95 in quarters and dimes. if the number of quarters is 6 more than the number of dimes, how many quart
WARRIOR [948]
13 quarters
q=6+d
25q+10d=395
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7 0
3 years ago
Read 2 more answers
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
Explain which trig functions and identities produce circles, ellipses and hyperbolas.
Lemur [1.5K]
Note that we can also write equations for circles<span>, </span>ellipses, and hyperbolas<span> in terms of cos and sin, and other </span>trigonometric functions<span>; there are examples of these ...</span>
7 0
4 years ago
Find the slope of the line (-4, -1) (1, 4)
timofeeve [1]

(y - yo) = m.(x - xo)

We have two points (-4, -1) and (1, 4)

(-1 - 4) = m.(-4 - 1)

(-5) = m.(-5)

m = (-5)/(-5)

m = 1

So the slope is 1

7 0
4 years ago
Read 2 more answers
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