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Sophie [7]
3 years ago
5

Before sunrise, the temperature was 22.4°F below zero. By noon, it had risen 12.8°F. What expression can be used to find the

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
8 0

Answer:

-22.4+12.8

Step-by-step explanation:

If the temperature started at 22.4 below zero you would write that as -22.4 because it had risen 12.8 degrees you would add those 12.8 degrees to -22.4

MrMuchimi3 years ago
6 0

Answer:-22.4+12.8

Step-by-step explanation:

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4 0
3 years ago
PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.
Step2247 [10]

After using the property of power, the expressions as a power of the number a is (a^3)^{-2} = a^{-6} , (a^{-1}\cdot a^{-2})^{-3} = a^{9} and ((a^2)^{-2})^2=a^{-8} .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is (a^3)^{-2}.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

Simplifying the expression.

(a^3)^{-2} = a^{3*(-2)}

(a^3)^{-2} = a^{-6}

The second expression is (a^{-1}\cdot a^{-2})^{-3}

Using the property of multiplication of power; (a^m)^n=a^{mn}.

(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}

(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}

Using the property of sum of power a^m\cdot a^n=a^{m+n}

(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}

(a^{-1}\cdot a^{-2})^{-3} = a^{9}

The third expression is ((a^2)^{-2})^2.

Using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=((a^2)^{(-2)\times2})

((a^2)^{-2})^2=(a^2)^{-4}

Again using the property of multiplication of power; (a^m)^n=a^{mn}.

((a^2)^{-2})^2=a^{2\times(-4)}

((a^2)^{-2})^2=a^{-8}

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0
1 year ago
-6x + 7 (3x + 13) = -74
Sergio039 [100]

Answer:

the answer to the question is -11

3 0
3 years ago
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