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Alika [10]
3 years ago
7

.Given the functions f(n) = 500 and g(n) = (nine tenths)n _ 1, combine them to create a geometric sequence, an, and solve for th

e 11th term.
an = 500 _ (nine tenths)n _ 1; a11 _499.651

an = 500 + (nine tenths)n _ 1; a11 500.349

an = 500(nine tenths)n _ 1; a11 174.339

an = (500 ´ nine tenths)n _ 1; a11 340.732
Mathematics
2 answers:
Troyanec [42]3 years ago
5 0
It would be c hope this helps

weeeeeb [17]3 years ago
4 0
The original functions are: f(n) = 500 and g(n) = [9/10]^(n-1)

A geometric sequence combining them is: An = f(n)*g(n) = 500*[9/10]^(n-1):

Some terms are:
A1= 500
A2 = 500*[9/10]
A3 = 500*[9/10]^2
A4 = 500*[9/10]^3
....
A11 = 500*[9/10]^10 ≈ 174.339

Answer: the third option, An = 500[9/10]^(n-1); A11 = 174.339

 
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mars1129 [50]

Answer: (D) 1.99x + 1.89y = 9.57

Step-by-step explanation: The reason is because equation option D states that for every notepad and pencil, x and y he bought, the total of his bill would equal $9.57.

6 0
3 years ago
The ratio of losses to wins for Kyle's team is 3 to 2. If the team had played the same number of games, but had won twice as man
Fiesta28 [93]

Answer: The new ratio will be 1/4

Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.

So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.

So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4

4 0
2 years ago
Read 2 more answers
Necesito ayuda por fis​
svet-max [94.6K]

Answer:

pues que es en que necesitas ayuda

Step-by-step explanation:

dime namas comentame y te ayudo

3 0
3 years ago
Can someone please graph this ASAP!!!! 30 points and brainly for the best answer!!!!!
Alenkinab [10]

Answer:

The equation is

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3 0
2 years ago
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How do I solve this?
andreev551 [17]

Answer:

x is in the range [-1,4]

Step-by-step explanation:

I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.

We are given the following inequality:

| 2x - 3 | <= 5

This implies two possible cases:

[1] -5 <= 2x -3

Or

[2] 2x - 3 <= 5

So let's solve x for both of these cases:

[1] -5 <= 2x - 3

 -2 <= 2x

 -1  <= x

[2]  2x - 3 <= 5

 2x <= 8

  x <= 4

So from these cases, we can say the following is true:

x >= -1  and x <= 4

Thus, we can write this in the form

-1 <= x <= 4

Or in interval notation:

{ x is element of reals | -1 <= x <= 4}

Also written as

x is in the range [-1,4]

Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.

Cheers.

4 0
3 years ago
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