Question

14. Simplify (4a^-4)^-3 a. –64x^9 b. x^12/64 c. -8x^12 d. -1/2x^4

Answer 1

Remember
$(ab)^c=(a^c)(b^c)$ and
$x^{-m}= \frac{1}{x^m}$

so
$(4a^{-4})^{-3}=(4^{-3})((a^{-4}^{-3})$=$( \frac{1}{4^3})(a^{12})= \frac{a^{12}}{64}$

answer would be B if we were using x