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3 years ago

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14. Simplify (4a^-4)^-3 a. –64x^9 b. x^12/64 c. -8x^12 d. -1/2x^4

1 answer:

Anvisha [2.4K]3 years ago

7 0

Remember
$(ab)^c=(a^c)(b^c)$ and
$x^{-m}= \frac{1}{x^m}$

so
$(4a^{-4})^{-3}=(4^{-3})((a^{-4}^{-3})$ = $( \frac{1}{4^3})(a^{12})= \frac{a^{12}}{64}$

answer would be B if we were using x

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

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Given:

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x lies in the III quadrant.

To find:

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Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

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$(-\dfrac{15}{17})^2+\cos^2 x=1$

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$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

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$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

we know that

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That means

1 unit in the drawing represent 40 units in the actual

or

1 inch in the drawing represent 40 inches in the actual

step 1

Find the actual dimensions of the living room

Multiply the dimensions of the living room in the drawing by 40

$Length:\ 6(40)=240\ in$

$Width:\ 4(40)=160\ in$

step 2

Convert inches to feet

Remember that

$1\ ft=12\ in$

To convert inches to feet , divide by 12

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$Length:\ 240\ in=240/12=20\ ft$

$Width:\ 160\ in=160/12=\frac{40}{3}\ ft$

step 3

Find the area in square feet

Multiply the length by the width

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Convert to mixed number

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What is the solution to the inequality - 6x + 5 > -1

ExtremeBDS [4]

[ Answer ]

$\boxed{X \ < \ 1}$

[ Explanation ]

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Subtract 5 From Both Sides

- 6x + 5 - 5 > -1 - 5

Simplify

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Multiply Both Sides By -1 (Reverse Inequality)

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Simplify

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Divide Both Sides By 6

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Simplify

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$\boxed{[ \ Eclipsed \ ]}$

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