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Gennadij [26K]
3 years ago
9

The price of two pairs and six apples is $14. The price of three pairs and nine apples is $21. Can you determine the unit prices

for pears and apples? Explain.
Mathematics
1 answer:
deff fn [24]3 years ago
6 0

Answer:

  no

Step-by-step explanation:

The second purchase is exactly half-again larger than the first purchase, so sheds no light on the relative costs of the items. The per-item costs can be found when the ratio of items purchased is different from one buy to another.

___

We can only say that the cost of 1 pear and 3 apples is $7.

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The sum of the radius of the base and the height of a solid cylinder is 37m. If the total surface area of the cylinder is 1628 m
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Answer:

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Step-by-step explanation:

From  T.S.A = 2\pirh + 2\pir^{2}

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           1628 = 2\pirh + 2\pir^{2}

            1628 =  ( rh + r^{2} ) 2\pi

 by dividing both side by 2\pi

             \frac{1628}{2\pi }=  rh + r^{2}

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           rh = 259.10 - r^{2}

        h = \frac{259.10 - r^{2} }{r}   <u>          </u>(1)

From Radius + Height = 37

       r + h = 37  <u>              </u>(2)

by substituting eqn 1 into 2

    r + \frac{259.10 - r^{2} }{r}   = 37

by multiplying r to both side

   r^{2} + 259.10 - r^{2} = 37r

     259.10 = 37r

   r = \frac{259.10}{37}

   r = 7.00 ≅ 7  

From Eqn 2

     r + h = 37

     7 + h = 37

     h = 37 - 7

     h = 30

so Volume of a cylinder = \pi r^{2} h

                  V = \pi * 7^{2} * 30

                  V = 4618.14m^{3}  ≅  4618m^{3}  

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