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inn [45]
3 years ago
6

Evaluate the expression below for x = 4, y = –5, and z = 2.

Mathematics
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

<h2>D. 76</h2>

Step-by-step explanation:

Put x = 4, y = -5 and z = 2 to the expression 3x² - 4y + xz and use PEMDAS:

3(4)² - 4(-5) + (4)(2)

= 3(16) + 20 + 8

= 48 + 20 + 8

= 76

kherson [118]3 years ago
3 0

Answer:

<h2>76</h2>

Step-by-step explanation:

Substitute the values into the expression

  • x = 4
  • y = –5
  • z = 2.

3x^2 -4y+xz

3(4)^2 -4(-5)+(-5)(2)

Use BIDMAS, or another alternative.

B - Brackets.

We don't have any operations in brackets. We only have integers on their own.

I - Indices.

(4)^2 = 16

Substitute this into the expression

(3)(16) - 4(-5) + (-5)(2)

D - Division, M - Multiplication

Two brackets side by side means multiply.

(3)(16) = 3 * 16 = 48

4(-5) = 4 * -5 = -20

(4)(2) = 4 * 2 = 8

Substitute this into the expression.

48 - -20 + 8

A - Addition, S - Subtraction

Two minus signs become addition.

However, two different signs means minus.

48 - -20 + 8

48 + 20 + 8

68 + 8

76

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Answer:

No solution

Step-by-step explanation:

Original Equation:

5x - 5 = 5x + 7

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So we already know that this equation is not true, making it no solution

Hope this helped

6 0
3 years ago
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
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Answer:

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Step-by-step explanation:

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\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

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Step-by-step explanation:

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Step-by-step explanation:

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