Answer:
15.5 seconds.
Step-by-step explanation:
From the time the driver activated the brakes until he stopped, he travelled 76 - 14 = 62 meters.
During this time the car slowed down from 8 m/s to 0 m/s.
Assuming the deceleration was constant during this time we can apply one of the equations of motion for constant acceleration:
s = (u + v)t / 2 where u = initial velocity, v = final velocity, s = distance and t = the time, so:-
62 = (8 + 0)t/ 2
62 = 8t/2
4t = 62
t = 15.5 seconds.
Answer:
1st Option;
j = 4.5
k = 2
Step-by-step explanation:
Let's solve for "j" first:
=> We know that by the definition of midpoint segment theorem we can say;
3j = 5j - 9
0 = 5j - 3j - 9
0 = 2j - 9
0 + 9 = 2j
9 = 2j
9/2 = j
4.5 = j
=> Now that we have j-value we use the same method to solve for k-value;
6k = k + 10
6k - k = 10
5k = 10
k = 10/5
k = 2
Therefore;
j = 4.5
k = 2
<u>So the first option would be correct!</u>
Hope this helps!
Answer:
B will be the answer...
Step-by-step explanation:
The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.
To do that, we need to multiply the first equation by 5.
5 (-x − 2y = 7)
-5x − 10y = 35
Add to the second equation. Notice the x terms cancel out.
(-5x − 10y) + (5x − 6y) = 35 + (-3)
-16y = 32
Combining this new equation with the first equation from system A will get us system B.
-x − 2y = 7
-16y = 32
The scale of the map is equal to 250 miles per 1.7 feet. or 250m/1.7ft. set up as a fraction.
Divide 250 by 1.7 to get how many miles are equal to just 1 foot.
250/1.7 = 147.058824 miles per 1 foot
Multiply that times 3.06 feet (the distance between C and D on the map)
147.058824m/1ft x 3.06ft = 450m
The actual distance between City C and City D should be 450 miles.
Answer:
Just taking my points back
