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-BARSIC- [3]
3 years ago
8

a chemist has two solutions of h2so he has one 40% concentration the other has 25% concentration how many liters of each solutio

n must be mixed to obtain 96 L of a 37% solution
Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

                         Qty                  %                  = Qty (%)

Solution 1:          x                   .40                  .40(x)    

Solution 2:  <u>    96 - x  </u>         <u>   .25     </u>          <u>   .25(96 - x)   </u>

   Mixture:       96                  .37              .40x + .25(96 - x)

                                         96(.37)      =    .40x + .25(96 - x)

                                           35.52     =    .40x +   24 - .25x

                                           35.52     =    .15x +   24

                                            11.52     =    .15x

                                             76.8     =     x

Solution 2: 96 - x  = 96 - 76.8   = 19.2

Answer: 76.8 L of 40% solution, 19.2 L of 25% solution


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Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

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Put (x,y)=(-1,1)

34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34

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