Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine. How many strawb
2 answers:
Answer:
There are <u>72 strawberries</u> in George's bag.
Step-by-step explanation:
Given:
Jasmine filled her bag with 12 strawberries. George filled his bag with 6 times as many strawberries as jasmine.
Now, to find the number of strawberries are in George's bag.
Number of strawberries in Jasmine bag = 12.
George filled his bag with 6 times as many strawberries as jasmine.
So, number of strawberries of George's bag is:
Therefore, there are 72 strawberries in George's bag.
Answer:
There are 72 strawberries in George's bag.
Step-by-step explanation:
Given:
Number of strawberries in jasmine bag = 12
We need to find Number of strawberries in George's bag.
Solution:
Now given that;
George filled his bag with 6 times as many strawberries as jasmine.
So we can say that;
Number of strawberries in George bag is equal to 6 multiplied by number of strawberries in Jasmine bags.
framing in equation form we get;
Number of strawberries in George bag =
Hence There are 72 strawberries in George's bag.
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Answer:
a)
b)
c)
When the acceleration is 0 we have:
And if we replace t=2 in the velocity function we got:
Step-by-step explanation:
For this case we have defined the following function for the position of the particle:
Part a
From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:
Part b
For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:
We can factorize this function as
So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is we need to analyze the following intervals:
For this case if we select two values let's say 0.25 and 0.5 we see that
And we see that for we have that f(b)>f(a) so then the function is decreasing on this case.
We have a minimum at t=2 since at this value w ehave the vertex of the parabola :
And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75
v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2
We see that the function would be increasing.
For this interval we will see that for any two points a,b with we have
for example let's say a=3 and b =4
The particle is moving to the right then the velocity is positive so then the answer for this case is:
Part c
When the acceleration is 0 we have:
And if we replace t=2 in the velocity function we got: