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Reptile [31]
3 years ago
11

A sample of 500 part-time students revealed that their annual incomes were normally distributed with a mean income of $30,000 an

d a standard deviation of $3,000. The number of students that earned between $27,000 and $33,000 is _________.

Mathematics
2 answers:
e-lub [12.9K]3 years ago
6 0

Answer:

341 students

Step-by-step explanation:

Here, we are to calculate the number of students earning between a particular range of income.

Please check attachment for complete solution and step by step explanation

AfilCa [17]3 years ago
4 0

Answer:

  y = 340 students

Step-by-step explanation:

Solution:-

- The sample of size, n = 500 part time students

- The random variable "X" is defined : annual incomes of part time students. The random variable "X" follows normal distribution with the following parameters (mean income, standard deviation):

                            X ~ N ( 30,000 , 3,000)

- The proportion of students p that earn between $27,000 and $33,000 are defined by:

                            p = P ( 27,000 < X < 33,000 )

- Standardize the test values:

                P ( (27,000 - 30000) / 3000 < Z <  (33,000 - 30000) / 3000 )

                P ( - 1 < Z < 1 )

- The empirical rule for the 68 - 95 - 99.7, states:

               p = P ( - 1 < Z < 1 ) = 0.68

- So the number of students "y" that get their income between $27,000 and $33,000 are 68% of the sample taken:

              y = 0.68*500

              y = 340 students

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