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dlinn [17]
3 years ago
9

Factor a^2b^2-7ab+10

Mathematics
1 answer:
pentagon [3]3 years ago
5 0
What you should do in this case is to see the terms that are repeated in the expression.
 We have then that the terms are a and b.
 Making a common factor we have:
 a * b (a * b -7) +10
 Answer:
 The equivalent expression is:
 a * b (a * b -7) +10
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Simplify 18-2[x + (x - 5)].<br> O8-4x<br> 28 - 4x<br> 28 - 2x
densk [106]

Answer:

28-4x

Step-by-step explanation:

Step 1: Open most inner bracket and simplify

=18-2(x+x-5)

=18-2(2x-5)

Step 2: Expand brackets by multiplying 2 in and simplify

=18-2(2x)-2(-5)

=18-4x+10

=28-4x

Therefore the answer is 28-4x

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3 years ago
What is the midpoint of the segment 7, -3 and -2, -10
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8 0
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Solve each system by eliminating one of the variables by addition or<br> subtraction.
Vlad1618 [11]

Answer:

1) x- y = 8

x + y = 12

eliminate one variable by adding the equations

2x = 20

divided by 2 on both sides

x = 10

substitute the value of x in the equation 1

10 - y = 8

-y = 8- 10

y =2

[x , y]

[10 , 2]

2) 2x - y = 4

3x + y = 6

eliminate one variable by adding the equations

5x = 10

x = 2

substitute the value of x in the equation

2(2) - y = 4

4 - y = 4

y = 0

[x ; y]

[2; 0]

3) x + 2y = 10

x + 4y = 14

multiply equation 1 by - 1

-x -2y = -10

x + 4y = 14

eliminate one variable by adding the equations

2 y = 4

y = 2

substitute the value of y in the equation 1

x + 2(2) = 10

x + 4 = 10

x = 6

[x ; y]

[6 ; 2]

4 ) 3x + y = 9

y = 3x + 6

simplify the expression

3x + y = 9

- 3x + y = 6

eliminate one variable by adding the equations

2y = 15

y = 15/2

substitute the value of y in equation 1

3x + 15/ 2 = 9

3x = 3/2

x = 1/2

[x ; y]

[1/2 ; 15/ 2]

5) 4x + 5y = 15

6x - 5y = 18

eliminate one variable by adding the equations

10 x = 33

× = 33/10

substitute the value of x in equation I

4 (33/10) + 5y = 15

66/5 + 5y =15

5y = 9/5

y = 9/25

[x ; y]

[33/10 ; 9/25]

6) 5x = 7y

x + 7y = 21

in equation I move the variable to the left

5x - 7y = 0

x + 7 y = 21

eliminate one variable by adding the equations

6x = 21

x = 7/2

substitute the value of x in the equation

5(7/2) = 7y

35/2 = 7y

5/2 = y

[x ; y ]

[7/2 ; 5/2 ]

4 0
3 years ago
Need this asap! questions in the ss
svetlana [45]

Answer/Step-by-step explanation:

Part A:

Evidence 1: the line passes through the point of origin, (0, 0)

Evidence 2: it has a unit rate or constant of proportionality, k = y/x = 5/3

Part B:

When extended, if the ray passes through the point, (18, 30), then y/x of this point, should give us the same unit rate (k) of 5/3 of the graph.

Thus:

y/x = 30/18

Simplify

= 5/3

Thus, it has the same unit rate of the graph, therefore, the ray passes through the point (18, 30).

7 0
3 years ago
What is an equation of the line that passes through the point (6,-4) and is perpendicular to the line 2x-y=5​
Novosadov [1.4K]
2x+y=8

this equation is perpendicular to 2x-y=5 and passes through the point (6,-4)

8 0
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