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kirza4 [7]
3 years ago
11

Three consecutive odd integers have a sum of 21 . find the integers.

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0
The three consecutive numbers are 5, 7, and 9.
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4y+8-2y if y=3 what is the answer
exis [7]

Answer:

14.

Step-by-step explanation:

Plug 3 in for y:

= 4(3) + 8 - 2(3)

= 12 + 8 - 6

= 14.

6 0
2 years ago
(-7)(-5)(2)? Its just like that so...
MAVERICK [17]

Answer:

70

Step-by-step explanation:

-7 × -5 = 35

35 × 2 = 70

8 0
3 years ago
Read 2 more answers
Question 2 of 10<br> What is the surface area of the rectangular pyramid below?
Ymorist [56]

Answer:

363

Step-by-step explanation:

11x11=121

((11x11)÷2)x4=11x11x2=121x2=242

121+242=363

5 0
2 years ago
Find the equivalent fractionsss with large denominatorsss
Stella [2.4K]

Answer:

12

Step-by-step explanation:

\frac{3}{8}  =  \frac{?}{32}

8*4=32

3*4=12

6 0
2 years ago
Assume f is a one to one function of f(x)= 4-6x find f^-1(-32)​
OleMash [197]

Answer:

f^-1(-32)=6

Step-by-step explanation:

<u>Find the inverse of the function f(x)=4-6x:</u>

f(x)=4-6x

y=4-6x

x=4-6y

x-4=-6y

(x-4)/-6=y

-1/6x+2/3=y

y=-1/6x+2/3

f^-1(x)=-1/6x+2/3

<u>Plug in f^-1(-32) for f^-1(x) and simplify:</u>

f^-1(-32)=-1/6(-32)+2/3

f^-1(-32)=16/3+2/3

f^-1(-32)=18/3

f^-1(-32)=6

5 0
3 years ago
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