Answer:
i would think b.. but im not sure
Step-by-step explanation:
Step-by-step explanation:
<h3>a. </h3>




<h2>______________</h2>
<h3>B. </h3>




<h2>______________</h2>
<h3>C. </h3>




<h2>______________</h2>
<h3>D. </h3>



<h2>______________</h2>
<h3>E. </h3>




Answer:
10m.
Step-by-step explanation:
Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...
2*1 = 2 5*1 = 5
2*2 = 4 5*2 = 10
2*3 = 6
2*4 = 8
2*5 = 10
Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.
5
3y=15-4x
y=5-4/3x
so the answer is 5
Answer:
-2
Step-by-step explanation:
add 3 to 11 and then divide 14 by -7