A child makes a pitcher of fruit punch by completely dissolving fruit- flavoured powder in water. The child drinks a glass and decides the punch needs to be sweeter, so she stirs in more powder. This time the powder does not all dissolve, but settles on the bottom of the pitcher. A) Is the fruit-flavoured powder a pure substance or a mixture? * helpme anyone?
The perimeter is the sum of side lengths. Opposite sides of a rectangle are the same length, so the perimeter is
P = 11 +43 5/12 +11 +43 5/12
= 2(11 +43 5/12)
= 2(54 5/12)
P = 108 5/6 . . . . feet
The area is the product of length and width. It doesn't matter which of the given dimensions you consider length or width, since you multiply them either way.
A = 11 * 43 5/12
= 473 +55/12
A = 477 7/12 . . . . square feet
The answer would be 314.16 square cm
Hope this helps! :)
Answer:
Step-by-step explanation:
Consider Cotters paid "x" dollars:
According to given condition:
Moores paid "x+6" dollars.
Both paid total $30
Hence,
(x) + (x+6) = 30
Solving for x:
2x +6 = 30
2x = 30-6
2x = 24
x = 24/2
x = 12
So amount paid by Moores = x +6 = 12+6 = $18
*****To find number of pairs of skates: price of one pair must be given.
Please post complete question.
Answer:
a = 3, b = 0, c = 0, d = -2
Step-by-step explanation:
<em>To find the reflection Multiply the matrices</em>
∵ The dimension of the first matrix is 2 × 2
∵ The dimension of the second matrix is 2 × 3
<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>
2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix
![\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%26-1%5Cend%7Barray%7D%5Cright%5D)
× ![\left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%260%5C%5C0%260%262%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%281%2A0%2B0%2A0%29%26%281%2A3%2B0%2A0%29%26%281%2A0%2B0%2A2%29%5C%5C%280%2A0%2B-1%2A0%29%26%280%2A3%2B-1%2A0%29%26%280%2A0%2B-1%2A2%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%263%260%5C%5C0%260%26-2%5Cend%7Barray%7D%5Cright%5D)
Compare the elements in the answer with the third matrix to find the values of a, b, c, and d
∴ a = 3
∴ b = 0
∴ c = 0
∴ d = -2
