Let's see
In ∆ABE and ∆CBE
- BE=BE(Common side)
- AE=EC[Diagonals of a parallelogram bisect each other]
- <AEB=<BEC[90°]
So by
SAS congruence the triangles are congruent
AB=BC
Fact:-
It's already given AC is perpendicular to BD
- It means diagonals are perpendicular to each other
According to general property of rhombus this parallelogram is also a rhombus.
So sides are equal hence AB =BC
F(x) =x² - 10x, f⁻¹(x) =?
1st find the missing square of x²-10x, ==> (x-5)² - 25
y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5
Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}
Answer:
A. cos 60° = ; x = 6 feet
Step-by-step explanation:
apex
Answer:
212 is the perimeter
Step-by-step explanation:
In a triangle, the midsegment is parallel to and half of non-intersecting side.
