The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
False.
Step-by-step explanation:
Answer:
x = 8.75, y = 8.125
Step-by-step explanation:
The triangles are similar thus the ratios of corresponding sides are equal, that is
=
( cross- multiply )
8x = 70 ( divide both sides by 8 )
x = 8.75
And
=
( cross- multiply )
8y = 65 ( divide both sides by 8 )
y = 8.125
Answer:
The answer is B 1/(5+x)
Step-by-step explanation: I just took this test on edgenuity and had trouble with this exact question