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3 years ago

Math question: -4x greater than equal to 8 please show work

Mathematics

2 answers:

Lisa [10]3 years ago

5 0

$-4x\geq8\\
x\leq-2$

cestrela7 [59]3 years ago

4 0

-4x is greater than or equal to 8

Divide both sides by -4

x is greater than or equal to -2

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4 years ago

Read 2 more answers

What is the measurement of each side of the perimeter is 94?

sveticcg [70]

2a+1 + 3a+2 +5a-9 you would start by combining like terms
2a+3a+5a= 10a
1+2-9= -6
10a-6=94
then subtract 94-6=88
then divide 88 by 10= 8.8
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3 years ago

The probability of it snowing in Eastern Canada tomorrow is 0.4. The probability of it snowing in Western Canada tomorrow is 2/5

Viktor [21]

Answer:

Neither

Step-by-step explanation:

They both have the same probability because 2/5 and 0.4 have the same value.

6 0

4 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago