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PilotLPTM [1.2K]
3 years ago
14

Calculate f(x) for the given domain values.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

See explanation

Step-by-step explanation:

1. The given function is

f(x) =  - 3x

The domain values are: x=0, 2, -1, 4, -2

When x=0

f(0) =  - 3 \times 0 = 0

When x=2,

f(x) =  - 3 \times 2 =  - 6

When x=-1

f(x) =  - 3 \times  - 1  = 3

When x=4

f(4) =  - 3 \times 4 =  - 12

When x=-2

f( - 2) =  - 3 \times  - 2 = 6

2. The given function is

f(x) =  \frac{1}{3} x

When x=3,

f(3) =  \frac{1}{3}  \times 3 = 1

Similarly,

f( - 3) =  \frac{1}{3}  \times  - 3 =  - 1

f(300) =  \frac{1}{3}  \times 300 = 100

f( - 180) =  \frac{1}{3}  \times  - 180 =  - 60

f(99) =  \frac{1}{3}  \times 99 = 33

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Answer: Two and one tenth.
5 0
3 years ago
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
52.5 + s I need help please
sleet_krkn [62]

Answer:

try 00.1

Step-by-step explanation:

6 0
2 years ago
Who can help me with this plzz
Brrunno [24]
.04d + 20. 

This is because even with no miles they charge 20 more and then 4 cents more for any additional mile. 
6 0
3 years ago
Madison likes to go to her local hair salon because she is a premier member there. Her membership fee costs $80.00 and that memb
OlgaM077 [116]

By evaluating a linear equation, we can complete the table:

Number of visits   |  total cost

      2                            $132

      4                            $184

      5                            $210

      8                            $288

<h3>How to fill the table?</h3>

We know that her membership fee costs $80.00, and it allows her to get her hair done for $26.00 for each visit, so if she does x visits, then the total cost for these x visits (including the membership fee) is:

c(x) = $80.00 + $26.00*x

So we have a linear equation that models the total cost.

Evaluating the equation in the values of the table we will get the other values.

c(2) = $80 + $26*2 = $132

c(4) = $80 + $26*4 = $184

c(5) = $80 + $26*5 = $210

c(8) = $80 + $26*8 = $288

Then the complete table is:

Number of visits   |  total cost

      2                            $132

      4                            $184

      5                            $210

      8                            $288

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

7 0
1 year ago
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