For any point reflected in the y- axis
(x, y ) → (- x, y )
A(1, 1) → A'(- 1, 1)
B(5, 1 ) → B'(- 5, 1 )
C(3, 3 ) → C'(- 3, 3 )
Answer:
<h2>
cosecθ = 1/sinθ = 11/6√2</h2>
Step-by-step explanation:
Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.
Based on SOH, CAH, TOA;
cosθ = adjacent/hypotenuse = 7/11
adjacent = 7 and hyp = 11
Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.
Using pythagoras theorem to get the opposite;

sinθ = 6√2/11
cosecθ = 1/sinθ = 1/( 6√2/11)
cosecθ = 1/sinθ = 11/6√2
Note the error; cscθ
1/cosθ but cscθ = 1/sinθ
Answer:
x=11
Step-by-step explanation: