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Agata [3.3K]
3 years ago
11

X - 10 > 4x + 20 < x + 10

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

12

Step-by-step explanation:

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Use scientific notation to estimate the number of inches in 1,225 miles. Include all calculations in your final answer. 1 inch ≈
masya89 [10]
1225*(1.578*10^-5)=1.933*10^-2

1.578*10^-5= 0.00001578

1225*0.00001578=0.0193305

0.0193305=1.933*10^-2

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3 years ago
if the parent function is square root of x, describe the translation of this function square root x+7
kotykmax [81]

The function y=\sqrt{x} sits with its starting point at the origin. The function y=\sqrt{(x-h)}+k is translated h units to the left or right and k units up or down. Since our radicand, the value under the square root sign, is x+7, putting that into our standard form it would be x-(-7) because minus a negative is a positive. So we move the parent graph to the left (-7 moves to the left) 7 units. There is no number k so our function is not moving up or down. Only to the left 7.

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3 years ago
Mitchell has a small bag with 12 M&amp;Ms in it. 5 of the M&amp;Ms are yellow. 2 are green. 1 is orange. 4 is brown. what fricti
Sophie [7]

Answer:

1/3

Step-by-step explanation:

There are 4 brown M&Ms and 12 M&Ms in total.

Since both 4 and 12 are divisible by 4,

4/12 = 1/3

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3 years ago
Is water wet? (wrong answers only)
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Wet is a description or effect of something when a cause happens. So, water isn't wet, but when we touch it, we get wet. 
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Read 2 more answers
What is the equation of this line in standard form? (-4, -1) &amp; (1/2, 3)
BabaBlast [244]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{\frac{1}{2}}~,~\stackrel{y_2}{3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{\frac{1}{2}}-\underset{x_1}{(-4)}}}\implies \cfrac{3+1}{\frac{1}{2}+4}\implies \cfrac{4}{~~\frac{9}{2}~~}\implies \cfrac{4}{1}\cdot \cfrac{2}{9}\implies \cfrac{8}{9}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{8}{9}}[x-\stackrel{x_1}{(-4)}]\implies y+1=\cfrac{8}{9}(x+4) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{9}}{9(y+1)=9\left( \cfrac{8}{9}(x+4) \right)}\implies 9y+9=8(x+4)\implies 9y+9=8x+32 \\\\\\ 9y=8x+23\implies -8x+9y=23\implies 8x-9y=-23

4 0
3 years ago
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