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jarptica [38.1K]
3 years ago
15

Find the length of one side of a square if the perimeter of the square is 20 inches.

Mathematics
1 answer:
damaskus [11]3 years ago
7 0

Answer:

5 inches

Step-by-step explanation:

A square is all equal sides, so 20 inches divided by 4 is 5 inches.

Hope this helps :)

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Help i might be in love with my best friend what do i do??
Trava [24]

Answer:

Confess to him/her

Step-by-step explanation:

It might be awkward if you get rejected but atleast you say what you want to say

8 0
3 years ago
7m - 6 + 3m + 7 = 21
Hitman42 [59]

Answer: m = 2

Step-by-step explanation: Coz I juss know

8 0
3 years ago
Read 2 more answers
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
2 years ago
Find the values of x, y, and z.<br> X=?<br> Y=?<br> Z=?
astraxan [27]
I haven’t taken geometry in a couple years, so I hope this is right. I’m so sorry if it’s not!!

X= 91

Y= 62

Z= 45
4 0
2 years ago
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