Question

Help with solving for the variable in math problem: -3(3x)^2 + 3 = -6

Answer 1

To solve this problem, we first need to do the exponents (PEMDAS).

(3x)² is equal to 9x² Now we can substitute this back.

-3(9x²) + 3 = -6

Now we do multiplication

-27x² + 3 = -6

Now we can subtract 3 from each side to get the x on one side.

-27x² = -9

We can now divide each side by -27.

x² = 1/3

x = $\sqrt{\frac{1}{3}}$

x = -$\sqrt{\frac{1}{3}}$

Answer 2

Answer

x = 1/√3  and   x = -1/√3 

or in decimals x = + 0.577350269  and 

                           = - 0.577350269

Explanation

-3(3x)² + 3 = -6

-3×9x² + 3 = -6

-27x² = -6-3

-27x² = -9

x² =-9/(-27)

    = 9/27

x = +√(9/27)   

 x = 3/√27

= 3/√9×3

= 3/3√3

= 1/√3

or in decimals x = 0.577350269

Also x = -√(9/27)

x = +√(9/27)   

 x = -3/√27

     = -3/√9×3

     = -3/3√3

    = -1/√3

or in decimals x = -0.577350269