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masya89 [10]
4 years ago
12

Help with solving for the variable in math problem: -3(3x)^2 + 3 = -6

Mathematics
2 answers:
liubo4ka [24]4 years ago
8 0

To solve this problem, we first need to do the exponents (PEMDAS).


(3x)² is equal to 9x² Now we can substitute this back.


-3(9x²) + 3 = -6


Now we do multiplication


-27x² + 3 = -6


Now we can subtract 3 from each side to get the x on one side.


-27x² = -9


We can now divide each side by -27.


x² = 1/3


x = \sqrt{\frac{1}{3}}


x = -\sqrt{\frac{1}{3}}

lana66690 [7]4 years ago
6 0

Answer

x = 1/√3  and   x = -1/√3 

or in decimals x = + 0.577350269  and 

                           = - 0.577350269


Explanation

-3(3x)² + 3 = -6

-3×9x² + 3 = -6

-27x² = -6-3

-27x² = -9


x² =-9/(-27)

    = 9/27


x = +√(9/27)   

 x = 3/√27

= 3/√9×3

= 3/3√3

= 1/√3

or in decimals x = 0.577350269

Also x = -√(9/27)

x = +√(9/27)   

 x = -3/√27

     = -3/√9×3

     = -3/3√3

    = -1/√3

or in decimals x = -0.577350269

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