Answer:
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Step-by-step explanation:
We make the composition of both functions:
f (x) = x ^ 2-1
g (x) = 2x-3
Then:
f (g (x)) = (2x-3) ^ 2-1
Rewriting:
f (g (x)) = 4x ^ 2-12x + 8
The domain of this function is all real numbers.
Equivalently
x: (-inf, inf)
answer:
x: (-inf, inf)
option 1.
Answer:
0.1069 = 10.69%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
Between 57 and 69
This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So
X = 69
has a pvalue of 0.9918
X = 57
has a pvalue of 0.8849
0.9918 - 0.8849 = 0.1069 = 10.69%
Answer:
Step-by-step explanation:
1)
Percentile is related to the area under the standard normal curve to the LEFT of a certain data value (which in this case would be 26.1 inches).
On my Texas Instruments TI-83 Plus calculator, I found this area as follows:
normcdf(-100, 26.1, 28.4,1.2), where the range -100 to 26.1 represents the area (as a decimal fraction) to the left of 26.1 inches. My result was 0.028, which corresponds to the 3rd percentile (0.028 rounds off to 0.03, which would be 3rd percentile).
2) The mean waist size is 28.4 inches, represented by a vertical line through the standard normal curve lying between 24 and 32. We use the same function on the calculator: normcdf(24, 32, 28.4, 1.2).
The result is 0.9985. Subtracting this from 1.0000, we get 0.001, or 0.1%, which is the percentage of female soldiers requiring custom uniforms.
In order to answer this I have to see a visual
