The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
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42 is the answer
Explanation:
50% of 80 is half of 80 which is 40
Then you would add 40 with 5% of 40
What you would do then is 5% times 40 then you would change the 5% into a decimal which is 0.05 and multiply it by 40 , which would get u 2
Then you would add the price with tax
40+2 = 42
Answer:
Domain (0, ∞)
Range (-∞, ∞)
Step-by-step explanation:
The domain is the input values
The input is from 0 to infinity
Domain (0, ∞)
The range is the output values
The input is from negative infinity to infinity
Range (-∞, ∞)
Answer:
The answer is choice 3.
Step-by-step explanation:
I've had this equation b4
Its 12, becuse if its a Circle then you can look at it the same way you look at a clock which has 12 numbers on it and 4 and 11 are directly across each other.
