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3 years ago

Assume y varies directly as x.

Mathematics

1 answer:

BartSMP [9]3 years ago

7 0

Answer:

soln

let x=n in order to differentiate btn x and multiplication sign.

first of all we apply cross multiplication.

14/4×n/2

(4×n)=(14×2)

open blacket

4n=28

we divide by 4 both side

n=7

therefore

x=7

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Its about differention

nika2105 [10]

Had -9-x^2
———
x^2

adh (-9-x^2)
——————-
x^2

-9adh-adhx^2
———————
x^2

9adh+adhx^2
- ———————
x^2

Hope this helps

6 0

3 years ago

The domain of an exponential function is

dalvyx [7]

Answer:

real numbers

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If we wish to obtain a 95% confidence interval of a parameter using the bootstrap method, we determine the _______ percentile

BigorU [14]

Answer:

2.5th percentile and the 97.5th percentile.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

So we obtain the 0.025*100 = 2.5th percentile and the (1-0.025)*100 = 97.5th percentile.

So the answer is:

2.5th percentile and the 97.5th percentile.

8 0

3 years ago

Which sum will be neither positive nor negative? 07+(-6) 0 3+2 0-6 + 6 0-4-(-4)

makkiz [27]

Step-by-step explanation:

The awnser is -6+6 because it would end up being 0, which is not positive nor negative

4 0

3 years ago

Graphs of Function,

andrew-mc [135]

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

Question 7

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

$(- \infty,-2)$

The function is decreasing when x > -2

$(-2, \infty)$

Additional information

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

$f(x)=-2x^2-8x-8$

$\implies f'(x)=-4x-8$

The function is increasing when $f'(x) > 0$

$\implies -4x-8 > 0$

$\implies -4x > 8$

$\implies x < -2$

The function is decreasing when $f'(x) < 0$

$\implies -4x-8 < 0$

$\implies -4x < 8$

$\implies x > -2$

This concurs with the observations made from the graph.

Question 8

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

$(- \infty,+ \infty)$

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

$[-4,1]$

Question 9

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

$(- \infty,-1)$

The function is increasing when x > -1

$(-1, \infty)$

5 0

2 years ago