If the area of the outer square is 4x2, then the area of the inner square is

1 answer:

6 0

Answered by the following sums - Outer square area = 4x^2 side of the square = 2x which is equal to diameter of circle == diameter of inner square. radius of circle = x diameter of outer square = 2*sqrt(2)*x consider side of inner square = a so a^2 + a^2 = (2x)^2 2a^2 = 4x^2 a = x*sqrt(2) So area of inner square will be = 2x^2

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Below is the solution:

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