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3 years ago

If the area of the outer square is 4x2, then the area of the inner square is

1 answer:

6 0

<span>Answered by the following sums - Outer square area = 4x^2 side of the square = 2x which is equal to diameter of circle == diameter of inner square. radius of circle = x diameter of outer square = 2*sqrt(2)*x consider side of inner square = a so a^2 + a^2 = (2x)^2 2a^2 = 4x^2 a = x*sqrt(2) So area of inner square will be = 2x^2</span>

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Examine the system of equations.

MakcuM [25]

Answer:

$\boxed{\boxed{\sf x=-3}}$

Step-by-step explanation:

$\sf y = -3x - 2$

$\sf y=7$

We'll substitute y into the equation:

$\sf 7 = -3x - 2$

Switch sides:

$\sf -3x-2=7$

Add 2 to both sides

$\sf -3x-2+2=7+2$

$\sf -3x=9$

Divide both sides by -3:

$\sf \cfrac{-3x}{-3}=\cfrac{9}{-3}$

$\sf x=-3$

Therefore, the value of x/solution is -3

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8 0

2 years ago

Read 2 more answers

HELPPPPPPPPP ASAPPPPPPPP PLSSSS

yanalaym [24]

-1/3(px-2) = 9

ok! so first we want to isolate x.

multiply both sides by -3/1 (this is the reciprocal of -1/3)

(px-2) = -27

px = -27 + 2

px = -25

x = -25/p

hope this helped!

8 0

3 years ago

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is

anastassius [24]

Answer:

$t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202$

$p_v =2*P(t_{(60)}>1.202)=0.234$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from 420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=424$ represent the sample mean

$s=26$ represent the sample standard deviation

$n=61$ sample size

$\mu_o =420$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:

Null hypothesis: $\mu = 420$

Alternative hypothesis: $\mu \neq 420$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=61-1=60$