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3 years ago

If the area of the outer square is 4x2, then the area of the inner square is

1 answer:

6 0

<span>Answered by the following sums - Outer square area = 4x^2 side of the square = 2x which is equal to diameter of circle == diameter of inner square. radius of circle = x diameter of outer square = 2*sqrt(2)*x consider side of inner square = a so a^2 + a^2 = (2x)^2 2a^2 = 4x^2 a = x*sqrt(2) So area of inner square will be = 2x^2</span>

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3 years ago

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3 years ago

Can someone please solve this problem for me?

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Answer:

5 and 7.

Step-by-step explanation:

Hey! So to start you need to create an algebraic expression. You can express this problem through the following equation:

*Note: if x is an odd integer, x + 2 is the next consecutive odd integer.

$x *(x+2)=35$

Expanding, you get:

$x^{2}+2x = 35.$

And moving the 35 to the other side, you get a simple quadratic.

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