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3 years ago

Plz Help FAST!!! Proportional relationship Study Island

Mathematics

1 answer:

OLEGan [10]3 years ago

7 0

Answer:

i think its 0.017857142

Step-by-step explanation:

because i divided 2 by 112 and 4 by 224 they both had that answer sorry if im wrong

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Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!

I am Lyosha [343]

Answer:

13 l of 15%, 13 l of 25%, 26 l of 70%

Step-by-step explanation:

solutions:

15%, 25% and 70%

final solution:

52 l of 45%

This includes 0.45*52l= 23.4 l acid

Let's assume:

amount of 15% solution= x
amount of 25% solution= y
amount of 70% solution= z
and we have z=2y

so there are 2 equation:

x+y+z=52

0.15x+0.25y+0.7z=23.4

x+y+2y= 52 ⇒ x+3y= 52 ⇒ x= 52- 3y

0.15x+0.25y+1.4y=23.4

0.15x+1.65y=23.4
0.15*(52-3y)+1.65y=23.4
7.8-0.45y+1.65y=23.4
1.2y=23.4-7.8
1.2y= 15.6

y=15.6/1.2
y= 13 l

--------

x= 52- 3*13= 13 l
z= 2y= 2*13= 26 l

6 0

3 years ago

Chu want some points? Answer correctly n ill give em to ya;)<br><br> 4+7

Andrej [43]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which equation(s) represents proportional relationship(s) with a constant of proportionality equal to 2?

In-s [12.5K]

Answer:

y=2x

Step-by-step explanation:

6 0

2 years ago

From the top of a 100 ft air traffic control tower, an airplane is observed flying in at an angle of 32\displaystyle \degree°. I

dolphi86 [110]

Answer:

1974.6 feets

Step-by-step explanation:

The plane's altitude is : h + 100 feets

To obtain h, according to the attached picture ;

We can use trigonometry :

Tan θ = opposite / Adjacent

Opposite = h ; adjacent = 3000 feets

Tan 32° = h / 3000

h = 3000 * 0.6248693

h = 1874.6080

Plane's altitude :

h + 100 feets

(1874.6080 + 100) feets

= 1974.6 feets

4 0

3 years ago

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0

3 years ago