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First lets find -8.2 x 10 = -82 know we find 82^5 which is 82*82*82*82*82
-82*-82=6724 and then 6724*-82= -551368 and then -551368*-82 =45212176 and then 45212176*-82= -3707398432 and finally -3707398432 is our answer i checked the calc to after i did the hard math that took me forever i had some help from the calc and i got this hopefully this helps
Answer:
The weight of the package is 1 kilograms.
It will cost $ 13 by both the couriers services.
Step-by-step explanation:
Let the weight of her package is x kilograms
Now, according to the question:
The charges of first Courier = $10 + $3(x)
and The charges of Second Courier = $7 + $6(x)
Also, for x kilograms, both the charges are equal
⇒ $10 + $3(x) = $7 + $6(x)
or, 10 + 3x = 7 + 6x
or, 10 -7 = 6x - 3x
⇒ 3x = 3, implies x = 3/3 = 1
⇒ The weight of the package is 1 kilograms.
It will cost : 10 + 3(1) = $ 13 = 7 + 6(1) by both the couriers services.
This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5
