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Julli [10]
3 years ago
14

Solve for brainlist :)

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

option A is correct

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>

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a rocket is 1 mile above thw earth in 30 seconds and 5 miles above the earth in 2.5 minutes what is the rockets rate of change i
Veronika [31]
Rate of Change:

At 1 mile in 30 seconds.
At  5 miles in 2.5 minutes.  2.5 minutes = 2.5*60 = 150 seconds.

Rate of change =   Change in height / Change in time

                            =   (h₂-h₁)/(t₂-t₁)

                            =   (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.

                             = (1/30) miles per second or 0.0333 miles per second.


To have the answer in miles per minute.

         (1/30) miles per second = (1/30) miles/second.

60 seconds = 1minute
1 second = (1/60) minute.

(1/30) miles/second  =  (1/30) miles/(1/60)minute
                                   =   (1/30) *60 miles / minute
                                   =    2 miles per minute.
8 0
3 years ago
The two-way frequency table shows data on accidents in the last year for drivers who took a driver
Galina-37 [17]

Answer:idk help

Step-by-step explanation:

4 0
2 years ago
Please help me!!! i hate math well most of it any way lol.
Alja [10]

Answer:

y= 2x

Y = total earned. X= the number of cups sold.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
SEND HELP YO Find and simplify the area (You need to completely multiply it out and include units in your answer):
Ad libitum [116K]

Answer:

Area = 2m^8 - 6m^4 + 4.5

Step-by-step explanation:

Given

Base = 2m^4 - 3

Height = 2m^4 - 3

Required

The area

This is calculated as:

Area = 0.5 * Base * Height

Area = 0.5 * (2m^4 - 3) * (2m^4 - 3)

Open brackst

Area = 0.5 * (4m^8 - 6m^4 - 6m^4 + 9)

Area = 0.5 * (4m^8 - 12m^4 + 9)

Open bracket

Area = 2m^8 - 6m^4 + 4.5

5 0
2 years ago
Solve the following equation: lim x-&gt;0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
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