3 years ago

Given: AB = 3y - 1, BC = 7y, AC = 29 Prove: AB = 8

Mathematics

1 answer:

Kobotan [32]3 years ago

7 0

AB + BC = AC
3y - 1 + 7y = 29
10y - 1 = 29
10y = 29 + 1 = 30
y = 30/10 = 3

AB = 3(3) - 1 = 9 - 1 = 8

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