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Aloiza [94]
3 years ago
13

Given: AB = 3y - 1, BC = 7y, AC = 29 Prove: AB = 8

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0
AB + BC = AC
3y - 1 + 7y = 29
10y - 1 = 29
10y = 29 + 1 = 30
y = 30/10 = 3

AB = 3(3) - 1 = 9 - 1 = 8
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