Answer:
55 adult tickets were sold on Friday.
Step-by-step explanation:
A linear system will be used to model the system.
Let c be the number of child tickets and a be the number of adult tickets
Then according to given statements
![a+c = 133\ \ \ \ Eqn\ 1\\9.50a+5.20c = 928.10\ \ \ Eqn\ 2](https://tex.z-dn.net/?f=a%2Bc%20%3D%20133%5C%20%5C%20%5C%20%5C%20Eqn%5C%201%5C%5C9.50a%2B5.20c%20%3D%20928.10%5C%20%5C%20%5C%20Eqn%5C%202)
From equation 1
![a = 133-c](https://tex.z-dn.net/?f=a%20%3D%20133-c)
Putting this in equation 2
![9.50(133-c)+5.20c = 928.10\\1263.5-9.50c+5.20c=928.10\\1263.5-4.3c = 928.10\\-4.3c = 928.10-1263.5\\-4.3c=-335.4\\\frac{-4.3c}{-4.3} = \frac{-335.4}{-4.3}\\c = 78](https://tex.z-dn.net/?f=9.50%28133-c%29%2B5.20c%20%3D%20928.10%5C%5C1263.5-9.50c%2B5.20c%3D928.10%5C%5C1263.5-4.3c%20%3D%20928.10%5C%5C-4.3c%20%3D%20928.10-1263.5%5C%5C-4.3c%3D-335.4%5C%5C%5Cfrac%7B-4.3c%7D%7B-4.3%7D%20%3D%20%5Cfrac%7B-335.4%7D%7B-4.3%7D%5C%5Cc%20%3D%2078)
Putting c = 78 in equation 1
![a+78 = 133\\a = 133-78\\a = 55](https://tex.z-dn.net/?f=a%2B78%20%3D%20133%5C%5Ca%20%3D%20133-78%5C%5Ca%20%3D%2055)
Hence,
55 adult tickets were sold on Friday.
Answer:
required time is here 45 minutes
Step-by-step explanation:
given data
apples = 100
bananas = 100
oranges = 100
pears = 100
solution
we have here 4 different kind of fruit
so that it is possible for each kind of fruit is
each kind of fruit is = 4 × 11 = 44
so each kind contain 11 fruit
as that 45th fruit make a dozen
now 1 fruit is pick every minute
'so we take here 45 minute to pick up 45 fruit
so that required time is here 45 minutes
X= 2 and x= -8/6 if you make it = 0
(10x-20)(6x+8)=0
10x-20=0
10x=20
x=2
6x+8=0
6x=-8
x=-8/6
Answer:
b
Step-by-step explanation:
Answer:
i think it's B 3.46
Step-by-step explanation:
hope this helps