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babymother [125]
3 years ago
9

What’s the correct answer for this question?

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

68°

Step-by-step explanation:

Angle IJK is 112

Opposite angles of a quadrilateral inscribed in a circle add up to 180°

So

m<IHK = 180-112

m<IHK = 68°

You might be interested in
The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….
Dominik [7]

Answer:

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

Step-by-step explanation:

Given

(x_1,y_1,z_1) = (1,3,-2)

(x_2,y_2,z_2) = (4,5,0)

(x_3,y_3,z_3) = (6,3,9)

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))

Substitute values of x and y in the given equation

C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))

C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))

C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})

<em>The above is the coordinate of the centroid</em>

8 0
3 years ago
A real estate agent wants to know how many owners of homes worth over​ $1,000,000 might be considering putting their home on the
JulsSmile [24]

Answer:

NO

Step-by-step explanation:

The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:

  1. N: The number of observations in the population.
  2. n: The number of observations in the sample.
  3. The way that the random sample is chosen.

We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is

μ_x=p

σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]

In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:

σ_x = σ / sqrt(n).

6 0
3 years ago
You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
Unpaid balance = $2,250 - $250 = $2,000



Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
8 0
4 years ago
Given:<br>AC – AR<br>&lt;1 = &lt;2<br>Prove:<br>&lt;3 =&lt;4<br><br>​
Katena32 [7]

Answer:

ΔCTA ≅ ΔDRA

Step-by-step explanation:

Triangles CTA and DRA are congruent by ASA postulate. This is because:

  • ∠1 ≅ ∠2 (given)
  • AC ≅ AR (given)
  • ∠A is the same for both triangles (they are opposite angles)

Then, correspondent angles and sides are congruent, for example, ∠3 ≅ ∠4

8 0
4 years ago
Apply a 90 degree rotation to the point (1, 2)
Makovka662 [10]
Hmm I use to know this wait a second I’ll answer it
7 0
3 years ago
Read 2 more answers
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