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babymother [125]
3 years ago
9

What’s the correct answer for this question?

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

68°

Step-by-step explanation:

Angle IJK is 112

Opposite angles of a quadrilateral inscribed in a circle add up to 180°

So

m<IHK = 180-112

m<IHK = 68°

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Plz read the question then solve
Oksi-84 [34.3K]

Answer:

A =80.5 ft^2

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh

The base is 14 ft and the height is 11.5 ft

A = 1/2 * 14 * 11.5

A =80.5 ft^2

3 0
3 years ago
Suppose you are offered just one slice from a round pizza (in other words, a sector of a circle). The slice must have a perimete
Andrew [12]
Dimeter is 28inch and area is equal to 26.7inch^2
6 0
3 years ago
I need more help thank
Soloha48 [4]

Answer:

B. 24

Step-by-step explanation:

Since both triangles are similar, therefore,

GM/XD = AG/KX

(x - 2)/6 = (x + 9)/9

Cross multiply

9(x - 2) = 6(x + 9)

9x - 18 = 6x + 54

Collect like terms

9x - 6x = 18 + 54

3x = 72

Divide both sides by 3

x = 72/3

x = 24

4 0
3 years ago
Question 2
REY [17]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
Let sin(−θ)=−3/5 and tanθ&gt;0. What is the value of cos(−θ)?
Jobisdone [24]

Answer:

The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = \frac{- 3}{5}

- sin Ф = \frac{- 3}{5}

So, sin Ф = \frac{ 3}{5}

Now, as sin Ф = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

So ,  \dfrac{\textrm perpendicular}{\textrm hypotenuse} =  \frac{ 3}{5}

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴  Base = \sqrt{16}

I.e Base = 4

Now, Cos Ф =  \dfrac{\textrm base}{\textrm hypotenuse}

So, Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Now , Since

Cos ( - Ф ) = Cos Ф

So,  Cos ( - Ф ) = Cos Ф =  \dfrac{\textrm 4}{\textrm 5}

Hence The value of  Cos (-Ф) \dfrac{\textrm 4}{\textrm 5} . Answer

6 0
3 years ago
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