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labwork [276]
3 years ago
15

RealTurf is considering purchasing an automatic sprinkler system for its sod farm by borrowing the entire $65,000 purchase price

. The loan would be repaid with four equal annual payments at an interest rate of 12%/year. It is anticipated that the sprinkler system would be used for 9 years and then sold for a salvage value of $9,000. Annual operating and maintenance expenses for the system over the 9-year life are estimated to be $13,000 per year. If the new system is purchased, cost savings of $25,000 per year will be realized over the present manual watering system. RealTurf uses a MARR of 15%/year for economic decision making. Show the internal rate of return used to reach your decision:
Business
1 answer:
lesantik [10]3 years ago
3 0

Answer:

The project return is lower than the minimum accepted of 15% thus not profitable for the company

Net Present Value -1.279,86‬

Explanation:

<u>Loan Present value</u>

PMT of the loan:

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\

PV 65,000

time   4

rate 0.12

65000 \div \frac{1-(1+0.12)^{-4} }{0.12} = C\\

C  $ 21,400.238

Present value at MARR:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C $21,400.24

time 4 years

rate 0.15

21400.2383598698 \times \frac{1-(1+0.15)^{-4} }{0.15} = PV\\

PV $61,097.2175

<u>Salvage value:</u>

\frac{Salvage }{(1 + rate)^{time} } = PV  

Salvage $9,000

time  9 years

rate  0.15000

\frac{9000}{(1 + 0.15)^{9} } = PV  

PV   2,558.36

<u>Cost savings present value:</u>

Cost savings per year:           25,000

less maintenance expenses (13,000)

net cash flow                          12,000

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C $ 12,000

time 9 years

rate 0.15

12000 \times \frac{1-(1+0.15)^{-9} }{0.15} = PV\\

PV $57,259.0070

Net Present Value

PV cost savings + PV salvage - PV loan payment

57,259 + 2,558.36 - 61,097.22 = -1.279,86‬

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Solution

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(a)

Optimization problem will be:

Max R = P x 15 x L^{0.2} x C^{0.8}

Subject to T = 50L + 100C

(b) When S = 50,000

Cost is minimized when (MPL / MPC) = w / r

MPL = \partialR / \partialL = P x 15 x 0.2 x (C / L)^{0.8} = P x 3 x (C / L)^{0.8}

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MPL / MPC = (3/12) x (C / L) = 50/100

C / 4L = 1/2

4L = 2C

2L = C

Substituting in production function,

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15 xL^{0.2} x (2L)^{0.8} = 50,000

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Note: This optimization problem can be solved without using Solver too, as shown here.

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Answer:

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Answer:

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