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3 years ago

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Alberto's birthday is 7 days before Corey's birthday. Alberto's birthday is on the 9th. Write the equation to find Corey's birth

day.

1 answer:

kvv77 [185]3 years ago

4 0

It is very simple you minus 9 from 7. 9-7=2. So Alberto's birthday is on the 2nd.

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Hi, could someone please help me with this Math problem, Thank you.

Naddik [55]

<h3>Explanation:</h3>

18. The 5 only needs to be "distributed" to terms that are inside the parentheses where 5 is on the outside. Here, the only term in the parentheses is 2x. Anne apparently also multiplied -3 by 5, erroneously. The -3 term is not inside the parentheses, so should be left alone when "distributing" the 5.

The left side of the equation simplifies to 10x -3, so Anne should have had ...

10x -3 = 20x +15

-18 = 10x . . . . . . . . . add -15-10x

-1.8 = x . . . . . . . . . . divide by 10.

The solution is x = -1.8.

___

19. Procedure: Subtract the right side of the equation from both sides. Use the distributive property as many times as necessary to eliminate parentheses. Collect terms. Divide by the coefficient of x. Subtract the constant.

5[3(x+4) -2(1 -x)] -x -15 = 14x +45 . . . . . . . original equation

5[3(x+4) -2(1 -x)] -x -15 -14x -45 = 0 . . . . . right side subtracted

5[3x+12 -2 +2x] -x -15 -14x -45 = 0 . . . . . . inner parentheses eliminated

15x +60 -10 +10x -x -15 -14x -45 = 0 . . . . . outer parentheses eliminated

(15 +10 -1 -14)x +(60 -10 -15 -45) = 0 . . . . . like terms associated

10x -10 = 0 . . . . . . . . . . . . . . . . . . . . . . . . . . simplified

x - 1 = 0 . . . . . . . . . divide by the coefficient of x

x = 1 . . . . . . . . . . . . subtract -1 (same as add 1)

The solution is x = 1.

5 0

3 years ago

Roberto ran 3/8 laps , juliette ran 2/3 laps and cora ran 1 1/4 laps. how many did they run together

ELEN [110]

Answer:

3 19/24

Step-by-step explanation:

$\frac{3}{8} + \frac{2}{3} + \frac{11}{4} = \frac{9 + 16 + 66}{24} = \frac{91}{24} = 3 \frac{19}{24 }$

hope it helps

3 0

2 years ago

Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).

grandymaker [24]

Answer:

Option (B)

Step-by-step explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line ( $m_1$ ) = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{2-1}{0-3}$

= $-\frac{1}{3}$

Let the slope of a parallel to the line given in the graph = $m_2$

By the property of parallel lines,

$m_1=m_2$

$m_2=-\frac{1}{3}$

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope = $-\frac{1}{3}$ will be,

$y-0=-\frac{1}{3}(x+3)$

$y=-\frac{1}{3}x-1$

Option (B). will be the answer.

5 0

3 years ago

A rectangle is drawn on a coordinate plane. Three vertices of the rectangle are points L(−3,10) , M(6,10) , and P(−3,−6) . Point

vovangra [49]

Hello!
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The answer is 16.
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Hope this helps and have a great day!

3 0

3 years ago

Read 2 more answers

Recall that the primes fall into three categories: Let Pi be the set of

a_sh-v [17]

Answer:

Check the explanation

Step-by-step explanation:

(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n

(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)

Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1

(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite

4 0

3 years ago