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Len [333]
3 years ago
7

The quadratic equation y=2x^2-px+6 has equal roots. Find the possible values of p.

Mathematics
1 answer:
Cloud [144]3 years ago
5 0
\Delta=0\\
\Delta=(-p)^2-4\cdot2\cdot6=p^2-48\\
p^2-48=0\\
p^2=48\\
p=\sqrt{48} \vee p=-\sqrt{48}\\
p=4\sqrt3 \vee p=-4\sqrt3

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