3 years ago

The quadratic equation y=2x^2-px+6 has equal roots. Find the possible values of p.

1 answer:

5 0

$\Delta=0\\
\Delta=(-p)^2-4\cdot2\cdot6=p^2-48\\
p^2-48=0\\
p^2=48\\
p=\sqrt{48} \vee p=-\sqrt{48}\\
p=4\sqrt3 \vee p=-4\sqrt3
$

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