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4 years ago

784,072 rounded to the nearest hundred thousand

1 answer:

3 0

When you round; you round down if the number in the selected column is below 5 and you round up if the number is 5 and above.

Thus; if you apply this to your question:

784,072 then round up and you get 790,000

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REPRESENT A PROBLEM: Six friends share 5 meat pies. Each friend first eats half of a meat pie. How much more meat pie does each

lord [1]

I cannot draw a picture, you can.

6 friends multiplied by 1/2 a pie each is 3 pies. That leaves 2 pies to divide evenly among 6 friends. 2/6 = 1/3. One third more pie more for everyone.

7 0

3 years ago

Find m∠IUV if m∠TUI = 65° and m∠TUV = 147°

victus00 [196]

The measure of the m∠IUV using the addition postulate is equivalent to 82 degrees

<h3>Lines and angles</h3>

A line is defined as the shortest distance between two points while an angle is the point where two lines meet.

Given the following measure of angles

m∠TUI = 65° and

m∠TUV = 147°

Required angle

m∠IUV

Using the addition postulate below

m∠TUV = m∠TUI + m∠IUV

Substitute the given parameters

147 = 65 + m∠IUV

m∠IUV = 147 - 65

m∠IUV = 82 degrees

Hence the measure of the m∠IUV using the addition postulate is equivalent to 82 degrees

Learn more on addition postulate here: brainly.com/question/2134445

#SPJ1

3 0

2 years ago

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 83 type K batteries and a sample of 77

agasfer [191]

Answer:

1. Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$ {mean voltage for these two types of

batteries is same}

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$ {mean voltage for these two types of

batteries is different]

2. Test Statistics value = -5.06

4. Decision for the hypothesis test is that we will reject null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, $\mu_1$ = true mean voltage for type K batteries.

$\mu_2$ = true mean voltage for type Q batteries.

So, Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$ {mean voltage for these two types of

batteries is same}

Alternate Hypothesis, $H_1$ : $\mu_1\neq \mu_2$ {mean voltage for these two types of

batteries is different]

The test statistics we use here will be :

$\frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ follows $t_n__1+n_2-2$

where, $X_1bar$ = 9.29 and $X_2bar$ = 9.65

$s_1$ = 0.374 and $s_2$ = 0.518

$n_1$ = 83 and $n_2$ = 77

$s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(83-1)0.374^{2}+(77-1)0.518^{2} }{83+77-2} }$ = 0.45 Here, we use t test statistics because we know nothing about population standard deviations.

Test statistics = $\frac{(9.29-9.65) - 0 }{0.45\sqrt{\frac{1}{83}+\frac{1}{77} } }$ follows $t_1_5_8$

= -5.06

At 0.05 or 5% level of significance t table gives a critical value between (-1.98,-1.96) to (1.98,1.96) at 158 degree of freedom. Since our test statistics is less than the critical table value of t as -5.06 < (-1.98,-1.96) so we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that mean voltage for these two types of batteries is different.

7 0

3 years ago

the sum of ones digit and tens digit is also 10. However, my ones digit is greater than my tens digit. i am a prime number less

Naddik [55]

The number that would fit is 37.

7 0

3 years ago

Please help :P QUESTION: "Choose the correct equation for each of the lines in the graph below."

faust18 [17]

The correct like is C.

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3 years ago

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