Whats the Area? how do i find it? In these specific questions?

Mathematics

1 answer:

just olya [345]3 years ago

7 0

The formula for finding the area of a square is:
${s}^{2}$

The formula for finding the area of a triangle is:
$\frac{1}{2} bh$

So for the square the area would be:
${2x}^{2} \times {2x}^{2} = {4x}^{2}$

The area for the triangle would be:

$\frac{1}{2} {2c}^{3} \times 4c = {4c}^{2}$

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Can someone explain (with steps) how to rationalize the following expression?

insens350 [35]

F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
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=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)

6 0

3 years ago

Solve x2 + 1/2x +1/16=4/9

kolezko [41]

<u>Answer:</u>

x = 0.417 or x = -0.917

<u>Step-by-step explanation:</u>

We are given the following expression and we are to solve it for the variable x:

$x ^2 + \frac { 1 } { 2 } x + \frac { 1 } { 1 6 } = \frac { 4 } { 9 }$