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lilavasa [31]
3 years ago
14

How do you solve 18x18

Mathematics
2 answers:
Romashka [77]3 years ago
7 0

Answer:

the answer is 324, I hope that helps!!

Amiraneli [1.4K]3 years ago
6 0
Do 18x18 which equals 324
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I think the answer is a cone
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\bf \cfrac{2}{5}\cdot \cfrac{3}{8}\implies \cfrac{\stackrel{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{5}\cdot \cfrac{3}{\underset{4}{~~\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{3}{20}

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2 1/5 × 5/6<br> (its a fraction) <br> PLSSS i need it now its a test
Soloha48 [4]

Answer:

\frac{11}{6} \ \ or \ 1\frac{5}{6}

Step-by-step explanation:

2\frac{1}{5} \times \frac{5}{6} \\\\ = \frac{11}{5} \times \frac{5}{6} \\\\=\frac{11}{6}\\\\=1 \frac{5}{6}

6 0
2 years ago
Read 2 more answers
Plz answer asap and i would be very grateful
goldfiish [28.3K]
The answer is C.

hope this helps
8 0
3 years ago
If
Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by \sqrt{x}

b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x}  }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\

Now, find a +b

a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}

Combine like terms

= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}

Now find (a + b)²

(a +b)² = (\frac{2\sqrt{x} }{x})^{2}

          = \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}

Hint: \sqrt{x} *\sqrt{x}  =\sqrt{x*x}=x

5 0
2 years ago
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