Volume of the conical tank = 1/3pi*r^2 * h = 1/3pi * (10/2)^2 * 15 = 125pi cubic feet or 392.7 cubic feet = 392.7 * 7.48 gallons = 2937 gallons.
Volume of the hemispherical tank = 2/3pi * r^3 = 2/3pi * (5.5)^3 = 348.5 cubic feet = 348.5 * 7.8 gallons = 2606 gallons
Hence the conical tank will contain more chemicals
X = 5
Isolate the variable by dividing each side by factors that don’t contain the variable.
Answer:
.46%
Step-by-step explanation:
.055/12= .00458= .46%
Answer:
108.60
Step-by-step explanation:
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