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Virty [35]
4 years ago
5

Factor completely, then place the answer in the proper location on the grid. 6x ^2 - 3x - 30

Mathematics
2 answers:
Stolb23 [73]4 years ago
7 0

Answer:

3(2x-5)(x+2)

Step-by-step explanation:

Given is an algebraic expression in x in degree 2 as

6x ^2 - 3x - 30

and we have to factor completely.

Seeing the coefficients we find that GCF is 3.

So 3 is a factor

Given expression =

3(2x ^2 - x - 10)\\

Inside product of last term and coefficient of I term is 20.

5x4 =20 and difference = -1 = the middle term

Hence

3(2x ^2 - x - 10)\\=3[2x^2-5x+4x-10]\\=3(2x-5)(x+2)

seraphim [82]4 years ago
3 0
Factor out the GCF first
3(2x² - x - 10)
3(2x - 5)(x + 2)
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Answer:

$1.9

Step-by-step explanation:

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3 years ago
Prove whether the quadrilateral is a parallelogram using the Distance & Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -
amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80

E(5, 2), F(4, -4)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

F(4, -4), G(-6, -12)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80

G(-6, -12),  D(-5, -6)

d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08

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WILL REWARD BRAINLIEST!!!
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Answer:

D.40°

Step-by-step explanation:

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