The answer would be 0,3,8,15,24,35,48,63
4 A) 1/6
4 B) 1/45
4 C) 2/3
4 D) 3/5
Answer:
It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.
Step-by-step explanation:
Micheal runs 3 miles in one hour or 60 minutes.
In one minute he runs 3/60= 1/20 or 0.05miles.
Jack runs 4.5 miles in one hour or 60 minutes.
In one minute he runs 4.5/60= 45/600= 9/120= 3/40 or 0.075 miles.
So Jack is 0.075/0.05 = 1.5 times faster than Micheal.
or Micheal is 1.5 times slower than Jack.
Jack starts from 2:20 pm and at 3 pm he will run 0.075(40 minutes)= 3miles
Micheal start at 2:00 pm and at 3 pm he will run 0.05(60 minutes)= 3 miles
So at 3 pm both will have covered equal distance= 3miles.
It will take Jack 40 minutes to cover the same distance which Micheal covers in 60 minutes. Both will meet at 3 miles distance at 3 pm.
The greatest common factor of 10 is 10 and the least common factor of 15 is 15
Hope I helped!!!!!
Hoarder of erasers :o
Is this suppose to be a riddle or sum
