Answer:
the third one is the correct answer
Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
Let's say that FH and EG intersection is O,
So we have the following:
OF = 2
OH = 5
Just because F and H are midpoints it means that EO = OG = x
And as it's given the area S=35
On the other hand
S = OF*OG/2 + OG*OH/2 + OH*OE/2 + OE*OF/2 = 2*x/2 + x*5/2 + 5*x/2 + x*2/2 = 2*x + 5*x = 7*x = 35
7x = 35 so x = 35/7 = 5
Answer: 5 units
Answer:
Both of the equations are right because if you take s=4p, then reverse it, p=1/4 of s because 4 of p is equal to s so s/4 = p
Answer:
15.63 cm^3
Step-by-step explanation:
Assuming that the ice cube is a perfect cube, then all of the sides are equal. There for, each side is 2.5 cm.
v = l*w*h
v = 2.5 * 2.5 * 2.5
v = 6.25 * 2.5
v = 15.625 cm^3