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olga55 [171]
3 years ago
5

Find the amount of change and the percent of decrease in the number of Hurricanes from 2008 to 2009 and from 2010 to 2011. Compa

re the amounts of change and the percents of decrease.
PLZ HELP

Mathematics
1 answer:
AlekseyPX3 years ago
5 0
Well, in the chart for 2008 it has 8 hurricanes, in 2009 it has based on that bar, 3 hurricanes, the change is then 5, 8 - 3  = 5.

now if we take 8 to be the 100%, what is 5 off of it in percentage?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
8&100\\ 5&p
\end{array}\implies \cfrac{8}{5}=\cfrac{100}{p}\implies p=\cfrac{5\cdot 100}{8}\implies p = 62.5

now in 2010, there were 12 hurricanes, whilst looking at the bar, in 2011 there were only 7, so that's a change of 5.

if we take 12 to be the 100%, what is 5 off of it in percentage?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
12&100\\
5&p
\end{array}\implies \cfrac{12}{5}=\cfrac{100}{p}\implies p=\cfrac{5\cdot 100}{12}\implies p\approx 41.67
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Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
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Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value corresponding to 201 degrees of freedom and 5% significance level is 1.97196

E = t×sd/√n = 1.97196×6.1/√202 = 0.8 hg

Lower limit = mean - E = 28.3 0.8 = 27.5 hg

Upper limit = mean + E = 28.3 + 0.8 = 29.1 hg

95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

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Answer:   x ≤ 3

Step-by-step explanation:

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divide each side by 4

x≤3

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