(x-h)^2=4p(y-k)
vertex is (h,k)
p is the distance from focus to vertex and distance from vertex to directix (vertex is in middle of directix and focus)
if p is positive, the parabola opens up and the focus is above the directix
if p is negative, the parabola opens down and the focus is below the directix
we see the directix is over the focus (1>-1) so the parabola opens down and p is negative
distance from (5,-1) to y=1 is 2 units
2/2=1
p=-1 since p is negative
1 up from (5,-1) is (5,0)
veretx is (5,0)
(x-5)^2=4(-1)(y-0)
(x-5)^2=-4y is the equation
ofc i can help! hold up m y mom is vcalling
Here you go!! Hope it helps !!
Answer:
y=-3/5x+16
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(13-19)/(5-(-5))
m=-6/(5+5)
m=-6/10
simplify
m=-3/5
y-y1=m(x-x1)
y-19=-3/5(x-(-5))
y-19=-3/5(x+5)
y=-3/5x-15/5+19
y=-3/5x-3+19
y=-3/5x+16
