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Yanka [14]
3 years ago
12

7. Makayla's cell phone cost her $149.50 to fix but the repair guy gave her 40% off so it

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0
89.7 that’s the answer check first not
Vesna [10]3 years ago
3 0

Answer:

$89.7

Step-by-step explanation:

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H=7+44t-16^2
zalisa [80]

Answer:

When t=2.1753 & t=.5746 , h=27

Don't worry, I got you. Also, my calculator does too.

We set h equal to 27, because we want the height to be 27 when we solve for t.

That leaves us with:

27 = 7 + 44t - 16t^2

Simplify like terms,

20 = 44t - 16t^2

Move 20 onto the right side, so we can use quadratic equation

44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20

Using quadratic, you get

t=2.1753 & t=.5746

<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>

3 0
2 years ago
Identify a negative coterminal angle to 480°
Lisa [10]

Step-by-step explanation:

here's the answer to your question

8 0
3 years ago
The time (t) it takes to clean an office building is directly related to the number of people (p) working.
cricket20 [7]

Answer:

Step-by-step explanation:

The time is inversely related to the number of people working so that as the number of people working increases, the time required decreases

t = k p  

divide both sides by p  

t/p =k

4 0
3 years ago
Read 2 more answers
I am confused my teacher helped on the first problem but the rest didn't make sense any idea's?
Dovator [93]
2. The three points you need to mark on this graph are (1,2) (2,3) and (4,5); you then draw a line through all of these points and determine whether the inches of rainfall is proportionate to the number of hours. 

You mark those 3 points because at 1 hour, 2 inches of rain has fallen; at 2 hours, 3 inches of rain has fallen; and at 4 hours, 5 inches of rain has fallen 

7 0
3 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
2 years ago
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