Answer:
the answer for this problem is 6
Answer:
1771 possible ways
Step-by-step explanation:
In this case, we need to know first how many candidates are in total:
10 + 3 + 10 = 23 candidates in total.
Now, we need to choose 3 of them to receive an award. In this case, we have several scenarios, but as it's an award we can also assume that the order in which the candidates are chosen do not matter, so, the formula to use is the following:
C = m! / n! (m - n)!
Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:
C = 23! / 3! (23 - 3)!
C = 2.59x10^22 / 6(2.43x10^18)
C = 1771
So we have 1771 ways of choose the candidates.
Answer: The answer is because , hope this helps :)
Step-by-step explanation:
Answer:
- x = ±√3, and they are actual solutions
- x = 3, but it is an extraneous solution
Step-by-step explanation:
The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...
... x^2(6x -18) = (2x -6)(9)
... 6x^2(x -3) -18(x -3) = 0
...6(x -3)(x^2 -3) = 0
... x = 3, x = ±√3
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Alternatively, you can subtract the right side of the equation and collect terms to get ...
... x^2/(2(x -3)) - 9/(6(x -3)) = 0
... (1/2)(x^2 -3)/(x -3) = 0
Here, the solution will be values of x that make the numerator zero:
... x = ±√3
_____
So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.
_____
<em>Comment on the graph</em>
For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.
To solve this problem you must follow the proccedure shown below:
1. Amount of lemonade in pints:
1 <span>quart of water=2 pints
1 pint of lemon
(9 ounces of honey)(0.0625 pints/1 ounce)=0.56 pints
Total in pints=2 pints+1 pint+0.56 pints
Total in pints=3.56 pints
2. </span>Amount of lemonade in<span> cups:
Total in cups=(3.56 pints)(2 cups/1 pint)
Total in cups=7.12 cups
3. </span>Amount of lemonade in<span> ounces:
Total in ounces=(7.12 cups)(8 ounces/1 cup)
Total in ounces=56.96 ounces</span>