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vodomira [7]
3 years ago
12

A pizza place offers 4 different cheeses and 10 different toppings. In how many ways can a pizza be made with 2 cheese and 3 top

pings?
Mathematics
2 answers:
just olya [345]3 years ago
8 0
There is a total of 4 different cheeses and 10 different toppings.

From the 4 cheeses we are to select 2 cheeses.

To select the 1st cheese, we have 4 possibilities

To select the 2nd cheese, we have 3 possibilities left

Total = 4 * 3 = 12


From the 10 different toppings we are to select 3 cheeses.

To select the 1st topping, we have 10 possibilities

To select the 2nd topping, we have 9 possibilities left

To select the 3rd topping, we have 8 possibilities left

Total = 10 * 9 * 8 = 720

So the total number of ways pizza can be made:

= 12 * 720 = 8640

= 8640 ways.
slava [35]3 years ago
4 0
Six ways, I believe..
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You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
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a

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c

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d

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Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

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