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scoray [572]
3 years ago
6

The speed of a space station in orbit is about 1300 meters per second.How many kilometers per hour does the space station travel

?

Mathematics
1 answer:
dem82 [27]3 years ago
5 0

Answer:

4680 km / hour

Step-by-step explanation:

You can do this with a method called dimensional analysis. (I think you should check the speed. Are you sure it is that fast?)

\frac{1300 m}{sec}*\frac{1 km}{1000 m} * \frac{3600 sec}{1 hr}\\

1.3 * 3600 = 4680 km/hour

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Log2x (2x^2+8x-6) =2
irinina [24]

Answer:

2x^3+8x^2-3x=0

Step-by-step explanation:

2x (2x^2+8x-6)=2\\multiply-all-in-bracets-by-2x\\4x^3+16x^2-6x=2\\devide-all-by-2\\2x^3+8x^2-3x=0

5 0
3 years ago
Look at this graph.
Phoenix [80]

Answer:  y= 1/4 x + 500

Step-by-step explanation:

The slope is the difference in y-values divided by difference in x-values plus the starting constant value (500 on the graph)

700 - 600  is the difference in y-values = 100

800 - 400 is the difference in x-values  = 400

100/400 = 1/4

y = x/4 +500

7 0
3 years ago
F(x) = -x^2-3x<br> find f (10)
Effectus [21]

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    f*(x)-(-x^2-3*x)=0  

STEP

1

:

STEP

2

:

Pulling out like terms

2.1     Pull out like factors :

  fx + x2 + 3x  =   x • (f + x + 3)  

Equation at the end of step

2

:

 x • (f + x + 3)  = 0  

STEP

3

:

Theory - Roots of a product

3.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

3.2      Solve  :    x = 0  

 Solution is  x = 0

Equation of a Straight Line

3.3     Solve   f+x+3  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  f+x+3  = 0 and calculate its properties

Graph of a Straight Line :

 

 

Calculate the Y-Intercept :

Notice that when x = 0 the value of f is -3/1 so this line "cuts" the f axis at f=-3.00000

 f-intercept = -3/1  = -3.00000  

Calculate the X-Intercept :

When f = 0 the value of x is -3/1 Our line therefore "cuts" the x axis at x=-3.00000

 x-intercept = -3/1  = -3.00000  

Calculate the Slope :

Slope is defined as the change in f divided by the change in x. We note that for x=0, the value of f is -3.000 and for x=2.000, the value of f is -5.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of -5.000 - (-3.000) = -2.000 in f. (The change in f is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

   Slope     = -2.000/2.000 = -1.000  

Geometric figure: Straight Line

 Slope = -2.000/2.000 = -1.000

 x-intercept = -3/1 = -3.00000

 f-intercept = -3/1 = -3.00000

x = 0

3 0
2 years ago
The scale drawing of a rectangular room measures 10cm long by 6cm wide. The actual width of the room is 9 metres. What is the ac
Snezhnost [94]

Answer:

48 meters

Step-by-step explanation:

The first thing is to calculate the scale, since we know both widths it is possible:

we pass the 9 meters to centimeters = 900 cm

900/6 = 150

So the scale would be 1: 150

Which means that the length is 150 times bigger.

10 * 150 = 1500cm or what equals 15m

the perimeter is the sum of all the sides, therefore:

P = 15 + 15 + 9 + 9

P = 48

Which means that the perimeter of the room is 48 meters

8 0
3 years ago
The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nea
a_sh-v [17]
Check the picture below.

so the rhombus has the diagonals of AC and BD, now keeping in mind that the diagonals bisect each, namely they cut each other in two equal halves, let's find the length of each.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-2})\qquad &#10;C(\stackrel{x_2}{6}~,~\stackrel{y_2}{8})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{[6-(-4)]^2+[8-(-2)]^2}\implies AC=\sqrt{(6+4)^2+(8+2)^2}&#10;\\\\\\&#10;AC=\sqrt{10^2+10^2}\implies AC=\sqrt{10^2(2)}\implies \boxed{AC=10\sqrt{2}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;B(\stackrel{x_1}{-2}~,~\stackrel{y_1}{6})\qquad &#10;D(\stackrel{x_2}{4}~,~\stackrel{y_2}{0})\qquad \qquad BD=\sqrt{[4-(-2)]^2+[0-6]^2}&#10;\\\\\\&#10;BD=\sqrt{(4+2)^2+(-6)^2}\implies BD=\sqrt{6^2+6^2}&#10;\\\\\\&#10;BD=\sqrt{6^2(2)}\implies \boxed{BD=6\sqrt{2}}

that simply means that each triangle has a side that is half of 10√2 and another side that's half of 6√2.

namely, each triangle has a "base" of 3√2, and a "height" of 5√2, keeping in mind that all triangles are congruent, then their area is,

\bf \stackrel{\textit{area of the four congruent triangles}}{4\left[ \cfrac{1}{2}(3\sqrt{2})(5\sqrt{2}) \right]\implies 4\left[ \cfrac{1}{2}(15\cdot (\sqrt{2})^2) \right]}\implies 4\left[ \cfrac{1}{2}(15\cdot 2) \right]&#10;\\\\\\&#10;4[15]\implies 60

7 0
3 years ago
Read 2 more answers
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