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scoray [572]
3 years ago
6

The speed of a space station in orbit is about 1300 meters per second.How many kilometers per hour does the space station travel

?

Mathematics
1 answer:
dem82 [27]3 years ago
5 0

Answer:

4680 km / hour

Step-by-step explanation:

You can do this with a method called dimensional analysis. (I think you should check the speed. Are you sure it is that fast?)

\frac{1300 m}{sec}*\frac{1 km}{1000 m} * \frac{3600 sec}{1 hr}\\

1.3 * 3600 = 4680 km/hour

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Find the rectangular coordinates of the point ( -3, 1/2 π)
alexdok [17]

Answer:

x = -3 cos (\frac{\pi}{2})= 0

y = -3 sin (\frac{\pi}{2})= -3

And then the rectangular coordinates for this case are :

(x = 0 , y = -3)

Step-by-step explanation:

We have the following point given P = (-3, \frac{\pi}{2}) and we want to conver from polar to rectangular coordinates and we need to use the following formulas:

x = r cos \theta

y = r sin \theta

For this case we have that:

r = -3

And:

\theta = \frac{\pi}{2}

Replacing we got:

x = -3 cos (\frac{\pi}{2})= 0

y = -3 sin (\frac{\pi}{2})= -3

And then the rectangular coordinates for this case are :

(x = 0 , y = -3)

4 0
3 years ago
Work out the size of angle X
irina [24]

Answer:

117

Step-by-step explanation:

180-101 = 79

180-(79+38)

180-117

63

180-63=117

4 0
3 years ago
30 over 8 mixed fractions
Vitek1552 [10]
30/8 = 3 6/8 = 3 3/4
5 0
3 years ago
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Find an irrational number between -10 and -10.1.
Pavlova-9 [17]
   
Between two rational numbers there are an infinite number of irrational numbers.

Example:


- 5 \sqrt{3} -\sqrt{2}= 5 \times 1.7320508 - 1.41421356 \approx -10.0744676\\\\
-10.1 \ \textless \  -10,0744676 \ \textless \  -10



6 0
3 years ago
Find the distance between points P(2, 2) and Q(7, 4) to the nearest tenth.
kirill115 [55]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points P(2, 2) ans Q(7, 4). Substitute:

|PQ|=\sqrt{(7-2)^2+(4-2)^2}=\sqrt{5^2+2^2}=\sqrt{25+4}=\sqrt{29}\approx5.4

<h3>Answer: PQ = 5.4</h3>
8 0
3 years ago
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