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scoray [572]
2 years ago
6

The speed of a space station in orbit is about 1300 meters per second.How many kilometers per hour does the space station travel

?

Mathematics
1 answer:
dem82 [27]2 years ago
5 0

Answer:

4680 km / hour

Step-by-step explanation:

You can do this with a method called dimensional analysis. (I think you should check the speed. Are you sure it is that fast?)

\frac{1300 m}{sec}*\frac{1 km}{1000 m} * \frac{3600 sec}{1 hr}\\

1.3 * 3600 = 4680 km/hour

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The GCF of 28 and 64 is<br><br> 2<br> 4<br> 7<br> 8
konstantin123 [22]
The greatest comment factor of 28 and 64 is 4.

The factors of 28 are 28, 14, 7, 4, 2, 1.
The factors of 64 are 64, 32, 16, 8, 4, 2, 1.

The common factors of 28 and 64 are 4, 2.

the greatest one of the two factors is 4.
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2 years ago
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The ratio of the number of boys to the number of girls at school is 4:5. what fraction of the students are boys?
Arisa [49]
Boys to girls is 4:5.......added = 9

so 4/9 are boys and 5/9 are girls
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3 years ago
To which subset does the following number belong? √7
marishachu [46]
Irrational numbers. √7 is an irrational number.
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3 years ago
Find an angle in the normal range(0 degrees to 360 degrees, or 0 to 2pi radians) whose terminal side points in the same directio
liq [111]

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d) 9pi/8

Step-by-step explanation:

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3 years ago
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B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

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2 years ago
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