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3 years ago

14. Which of the following linear

Mathematics

1 answer:

Alla [95]3 years ago

8 0

D
Due to the question being the question

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A. 55<br> b. 70<br> c. 110<br> d. 125

morpeh [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

100 point to the first correct answer

miss Akunina [59]

Answer:

X ~ B(n, p)

Given: X ~ B(2, 5/17)

⇒ n = 2

⇒ p = 5/17

Binomial distribution formula:

$\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x$

As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):

$\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}$

$\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}$

$\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}$

**Probability Distribution Table attached**

5 0

2 years ago

Help on this one please??

xenn [34]

Answer:

C = ~50 deg

Step-by-step explanation:

Apply the cosine theorem:

cos(C) = (CA^2 + CB^2 - AB^2)/(2*CA*CB)

= (7.5^2 + 6.5^2 - 6^2)/(2*7.5*6.5)

= 0.6410

=> C = ~50 deg

Hope this helps!

7 0

3 years ago

Can someone help me with this problem:)

kogti [31]

Answer:

Therefore,

93.6 feet tall is the tower from the ground.

Step-by-step explanation:

Given:

x = Opposite side to angle 60

50 ft = Adjacent side to angle 60

7 ft = height of boy

So Height of the tower will be,

$Height\ of\ tower=x+7$

To Find:

Height of the tower = ?

Solution:

In Right Angle Triangle , Tangent Identity we have,

$\tan 60= \dfrac{\textrm{side opposite to angle 60}}{\textrm{side adjacent to angle 60}}$

Substituting the values we get

$1.732= \dfrac{x}{50}\\\\x=86.6\ ft$

Substituting "x" For Height of tower we get

$Height\ of\ tower=86.6+7=93.6\ ft$

Therefore,

93.6 feet tall is the tower from the ground.

5 0

3 years ago

a 1 =− 3 1 a, start subscript, 1, end subscript, equals, minus, start fraction, 1, divided by, 3, end fraction a i = a i − 1

MrRa [10]

Answer:

$S_{75}=-506.888989761$ X 10^{32}$

Step-by-step explanation:

Given the sequence

$a_1=-\dfrac{1}{3}\\ a_i=a_{i-1}\cdot (-3)$

$a_2=a_{2-1}\cdot (-3)=a_1 \cdot (-3) = -\dfrac{1}{3}\cdot (-3)=1\\a_3=a_{3-1}\cdot (-3)=a_2 \cdot (-3) = 1 \cdot (-3)=-3\\a_4=a_{4-1}\cdot (-3)=a_3 \cdot (-3) = -3 \cdot (-3)=9\\$

Therefore the sequence is:

$-\dfrac{1}{3}, 1, -3, 9, ...$

This is a geometric sequence where the:

First Term, $a_1=-\dfrac{1}{3}$

Common ratio, r =-3

We want to determine the sum of the first 75 terms.

For a geometric sequence, the sum:

$S_n=\dfrac{a_1(1-r^n)}{1-r} \\$

Therefore:

$S_{75}=\dfrac{-\dfrac{1}{3}(1-(-3)^{75})}{1-(-3)} \\\\=\dfrac{-(1-(-3)^{75})}{4*3}\\\\S_{75}=\dfrac{(-3)^{75}-1}{12}\\\\S_{75}=-506.888989761$ X 10^{32}$

5 0

3 years ago